Rework problem 22 from section 3.2 of your text, involving the colored balls. For this problem, assume the box contains 6 blue balls, 6 red balls, and 4 white balls, and that we choose two balls at random from the box. What is the probability of neither being blue given that neither is red

Step-by-step explanation:

Given , there are 6 blue balls, 6 red balls, and 4 white balls, and that we choose two balls at random from the box.

P(neither blue nor red) = 1-P(blue or red)

= 1- [P(blue)+P(red)-P(blue and red)]

Hence, the probability of neither being blue given that neither is red is .

4

Step-by-step explanation:

p=120 -5Q

when p = 80

80 = 120 -5Q

Q=8

and when p= 60

60 = 120 -5Q

Q=12

so, change in consumer surplus = 12-8

= 4