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Ответ:

reesemf2006

28.08.2020

$m< xyz=\frac{1}{2}(a-b)$

$m< xoy=b$

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

$m< xyz=\frac{1}{2}(mayor\ arc\ xy-minor\ arc\ xy)$

substitute the values

$m< xyz=\frac{1}{2}(a-b)$

the measure of angle xoy is equal to

$m< xoy=minor\ arc\ xy$ > by central angle

substitute the value

$m< xoy=b$

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