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182075
08.10.2019 •
Mathematics
Sam creates a game in which the player rolls 4 dice. what is the probability in this game of having at least 2 of the dice land on 5.
group of answer choices
0.11500044682
0.86898036859
0.01601918459
0.13101963141
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Ответ:
Option D
ANSWER:
Sam creates a game in which the player rolls 4 dice .The probability in this game of having at least 2 of the dice land on 5 is 0.1310196314
SOLUTION:
We need to find the probability of atleast 2 out of 4 dices landing on 5.
For our convenience, we will calculate the probability of atleast 2 out of dices not landing on 5, later we can subtract it form 1, so that we will get the required answer.
We know that P(Event) + P (not an Event) = 1 ------------ eqn (1)
There is only one “5” on the die out of six faces. So probability of not getting a 5 on single die is =![\frac{5}{6}](/tpl/images/0298/6393/2bbce.png)
probability of not getting a 5 any of the 4 dies is calculated by multiplying
four times. So we get
Now, probability of getting a 5 on single die is =![\frac{1}{6}](/tpl/images/0298/6393/c8870.png)
Probability of getting a 5 any one of the 4 dies =![\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} \times \frac{5}{6}](/tpl/images/0298/6393/af014.png)
We have, four dies, so we can get 5 on any of them, hence we need to multiply with 4. So we get
Now, probability of atleast 2 out of dices not landing on 5 =![\frac{625}{1296} + \frac{500}{1296}](/tpl/images/0298/6393/c93e2.png)
Using equation (1) = P(Event) + P(not an event) = 1
P(Event) + 0.8680 = 1
P(Event) = 1 – 0.8680
P(Event) = 0.1320
By observing the options we can conclude that answer is 0.1310196314
Ответ:
I’ll answer your question, i just wanna know what the equation is