Mathematics: Samuel found the difference of the polynomials. (15x^2+11y^2+8x)-(7x^2+5y^2+2x)= blankx^2+6y^2+6x What value is missing from his solution?

Samuel found the difference of the polynomials.

randee56

14.02.2022

Co-efficient of $x^{2}$ is missing.

It should be 8 $x^{2}$ .

Step-by-step explanation:

Given two polynomials:

1st polynomial: 15x^2+11y^2+8x

2nd polynomial: -7x^2+5y^2+2x

To find:

The value in the blank:

$(15x^2+11y^2+8x)-(7x^2+5y^2+2x)= \_\_ \ x^2+6y^2+6x$

Solution:

Here, we have 3 pair of like terms.

2 terms with $x^{2}$ , 2 terms with $y^{2}$ and 2 terms with .

Like terms can be subtracted.

Subtracting the terms with $y^{2}$ , the coefficients will get subtracted.

11y^2 - 5y^2 = 6y^2

Subtracting the terms with , the coefficients will get subtracted.

8x -2x=6x

Subtracting the terms with $x^{2}$ , the coefficients will get subtracted.

$15x^2 - 7x^2 =\bold{8}x^2$

Therefore, the answer is:

Co-efficient of $x^{2}$ is missing.

It should be 8 $x^{2}$ .

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kassandrarosario1115

28.04.2020

n + 8m = d

8m = d - n

m = (d - n) / 8

Step-by-step explanation:

hope it helps you

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