Mathematics: Sarah, Heather and Maya are launching a model rocket in the park. They set up their rocket to lauch at an angle and use their phones to record the flight path of the rocket. By estimating heights/times and using some of the math that they learned in Algebra 1, the girls derived a quadratic equation to describe the rocket s path. The rocket s height can be found using the following equation: h(t)=-42t^2+253t+2 Where t is the time in seconds and h(t) is the height in feet. Answer the following questions

Sarah, Heather and Maya are launching a model rocket

enrique3300

02.02.2022

Step-by-step explanation:

The rocket's path is modeled by the equation as follows :

h(t)=-42t^2+253t+2 ....(1)

t is time in seconds and h(t) is the height in feet.

(A) For maximum height, put $\dfrac{dh(t)}{dt}=0$

So,

$\dfrac{d(-42t^2+253t+2)}{dt}=0\\\\-84t+253=\\\\t=\dfrac{253}{84}\\\\t=3.01\ s$

Now put t = 3.01 s in equatioon (1)

$h(t)=-42(3.01)^2+253(3.01)+2\\\\h(t)=383\ \text{feet}$

(B) The general equation of motion as a function of time t is :

h(t)=-16t^2+ut+h_o

u is initial speed.

If we compare the given equation with this general equation, we found that u = 253 m/s

$-42t^2+253t+2=0\\\\t = 6.03\ s$

Therefore, these are the required solutions.

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davidmfox5890

22.04.2020

carpet

Step-by-step explanation:

CarryOnLerning

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