Mathematics: Segment yw is an altitude of triangle xyz. find the area of the triangle. z=(5,4), w=(5,-1), y=(8,-1), x=(5,-3) a)7.5 b)9.5 c)10.5 d)15

.00000003 i think but i might be wrong...

Segment yw is an altitude of triangle xyz. find

Ответ:

123niikee

29.07.2020

Mathematics

C)10.5

Step-by-step explanation:

Using distance formula,

Height of triangle =YW= $\sqrt{(5-8)^2+(-1-(-1))^2}=\sqrt{(-3)^2+(0)^2}=\sqrt{9}=3\ units$

Base of triangle (side opposite to the vertex of triangle from which for altitude is formed)XZ= $\sqrt{(5-5)^2+(4-(-3))^2}=\sqrt{(0)^2+(7)^2}=\sqrt{49}=7\ units$

Thus the area of the triangle= $\frac{1}{2}\times\ base\times\ height$

$=\frac{1}{2}\times3\times7=10.5\ units$

Hence, the area of triangle = 10.5 units

Segment yw is an altitude of triangle xyz. find the area of the triangle. z=(5,4), w=(5,-1), y=(8,-1

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Segment yw is an altitude of triangle xyz. find the area of the triangle. z=(5,4), w=(5,-1), y=(8,-1), x=(5,-3)
a)7.5
b)9.5
c)10.5
d)15

Ответ:

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