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yola32
05.10.2021 •
Mathematics
Set both inequalities greater than or less than zero. Transform the second inequality so both have the same inequality symbol. Apply the Transitive Property and solve. Make sure the leading coefficient is positive.
x-7>5 and 1-4y<6
x-7>5→
1-4y<6→
Combined inequality
a. 0>4y+7
b. X+2>0
c. X+4y>7
d. x-12>0
e. 0>(-4y-5)
f. X-4y>5
Solved
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Ответ:
What grade is this? answer and I will respond
Step-by-step explanation:
Ответ:
1-4y<6→
Combined inequality
a. 0>4y+7
b. X+2>0
c. X+4y>7
d. x-12>0
e. 0>(-4y-5)
f. X-4y>5
f. c. X+4y>7
To solve for x-7>5, apply the Transitive Property to reach 1-4y<6 which states that -1-16y<2 or 4y>2 or X+4y>7. Therefore c is the correct answer choice.
To solve for 1-4y<6, apply the Transitive Property to reach x-7>5 which states that X+2>0. Solve this equation to reach X+4y>7. Therefore f is the correct answer choice.
a. 0>4y+7→
b. X+2>0→
c. X+4y>7→
d. x-12>0→
e. 0>(-4y-5)→
f. X-4y>5 →
g. -3x+10<0 →
h. (x+3) (x-4) > 0 →
a. 0>4y+7→ 4y>7 → y>0
b. X+2>0→ -2>X → X<-10
c. X+4y>7→ X+4 (X) > 7 → X>3
d. x-12>0→ -12 >x → x<-1
e. 0>(-4y-5)→ -4y-5 <0 → y>5
f. X-4y>5 → X+4 (X) > 5 → X > -1
g. -3x+10<0 → -3x-30 <0→ x>30
h. (x+3) (x-4) > 0 → x(x-4) >0 → x≠ -4, X≠4, X≠-3, x ≠ 9, x ≠-12 or (x≠ 3, x≠ -1) and (X≠ 4, X≠ -3)
3. b
4. d
5. f
6. h
7. a
8. e
9 c 10 g 11 i 12 b
13 j 14 h 15 k
Ответ: