Show that the statement is true. If DE has endpoints D(−1, 8) and E(7, −2), then the midpoint M of DE lies in Quadrant I. The midpoint M is (
,
). M lies in
(select)
, since the x‐coordinate is
(select)
and the y‐coordinate isShow that the statement is true. If DE has endpoints D(−1, 8) and E(7, −2), then the midpoint M of DE lies in Quadrant I.

The midpoint M is (
,
). M lies in
(select)
, since the x‐coordinate is
(select)
and the y‐coordinate isShow that the statement is true. If DE has endpoints D(−1, 8) and E(7, −2), then the midpoint M of DE lies in Quadrant I.

The midpoint M is (
,
). M lies in
(select)
, since the x‐coordinate is
(select)
and the y‐coordinate is

23.58% probability that his score is at least 592.7

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X

In this problem, we have that:

If 1 of the men is randomly selected, find the probability that his score is at least 592.7.

This is 1 subtracted by the pvalue of Z when X = 592.7. So

has a pvalue of 0.7642.

1 - 0.7642 = 0.2358

23.58% probability that his score is at least 592.7