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monai2005
15.09.2019 •
Mathematics
Simplify the following surds :
1) 2√21 × √27 ÷ √343
2) 7√5 × √125 ÷ 2√27
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Ответ:
1)![\frac{18}{7}](/tpl/images/0231/6072/0cc51.png)
2)![\frac{175\sqrt{3}}{18}](/tpl/images/0231/6072/b9915.png)
Step-by-step explanation:
* Lets explain how to simplify a square root
1)
∵
×
÷ ![\sqrt{343}](/tpl/images/0231/6072/b1dbf.png)
∵
× ![\sqrt{7}](/tpl/images/0231/6072/69133.png)
∴
=
× ![\sqrt{7}](/tpl/images/0231/6072/69133.png)
∵
=
×
× ![\sqrt{3}](/tpl/images/0231/6072/ba4cb.png)
∵
×
= 3
∴
= ![3\sqrt{3}](/tpl/images/0231/6072/f1e40.png)
∴
×
=
∵
×
= 3
∵ 2 × 3 × 3 = 18
∴
×
= ![18\sqrt{7}](/tpl/images/0231/6072/95ad9.png)
∵
=
×
× ![\sqrt{7}](/tpl/images/0231/6072/69133.png)
∵
×
= 7
∴
= ![7\sqrt{7}](/tpl/images/0231/6072/356d2.png)
∵
×
÷
=
∵
÷
= 1
∴
×
÷
=
2)
∵
×
÷
∵
=
×
× ![\sqrt{5}](/tpl/images/0231/6072/dd7c7.png)
∵
×
= 5
∴
= ![5\sqrt{5}](/tpl/images/0231/6072/ab8a9.png)
∴
×
=
∵
×
= 5
∴
×
= 7 × 5 × 5 = 175
∵
=
×
× ![\sqrt{3}](/tpl/images/0231/6072/ba4cb.png)
∵
×
= 3
∴
= ![6\sqrt{3}](/tpl/images/0231/6072/981e8.png)
∴
×
÷
=
175 ÷
= ![\frac{175}{6\sqrt{3}}](/tpl/images/0231/6072/b68a5.png)
∵
not in the simplest form because
the denominator has square root
∴ Multiply up and down by![\sqrt{3}](/tpl/images/0231/6072/ba4cb.png)
∴
= ![\frac{175\sqrt{3}}{6\sqrt{3}*\sqrt{3}}](/tpl/images/0231/6072/005b8.png)
∴
= ![\frac{175\sqrt{3}}{18}](/tpl/images/0231/6072/b9915.png)
∴
×
÷
=
Ответ:
True.
Step-by-step explanation: