davishernandez357
04.12.2020 •
Mathematics
Solve by using the quadratic formula
x^2-4x=-2
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Ответ:
x=2+![\sqrt[]{2}](/tpl/images/0950/9194/3a01f.png)
or x= 2-![\sqrt[]{2}\\](/tpl/images/0950/9194/b4035.png)
Step-by-step explanation:
Ответ:
Step-by-step explanation:
Let w represent the width of the floor. Then the length of the floor is (w+4) and its area is ...
A = LW
525 = (w+4)(w)
w^2 +4w -525 = 0
(w -21)(w +25) = 0 . . . . factor the above
Solutions are ...
w = 21, w = -25
We are interested in the positive solution: w = 21.
The floor is 21 feet wide and 25 feet long.
Alternate solution
Sometimes, when the factors aren't obvious, it works well to write an equation for the average of the dimensions. Here, we can represent that with x, and use (x-2) for the width, and (x+2) for the length. Then we have ...
525 = (x-2)(x+2) = x^2 -4
529 = x^2
√529 = 23 = x
Then w=23 -2 = 21, and the length is w+4 = 25.