Solve $\frac{1}{3} t - 5 < t - 2 \le -3t + 7.$ Give your answer as an interval.

I'm going to assume you want to find the area and perimeter.

Note that the sides of a square are always the same.

Find the area [ A = bh ]

A = 4 2/9 * 4 2/9

A = 17 67/81

Find the perimeter [ P = 2b + 2h ]

P = 2(4 2/9) + 2(4 2/9)

P = 16 8/9

Therefore, the area is 17 67/81 and the perimeter is 16 8/9

Best of Luck!