Mathematics: Solve the equation 36x^2 25=0 a. 6/5i b. 5/6i c. 25/36i d. 36/25i

For implicit differentiation, you are using the chain ruleExcept u(x) = y, So after every y term is differentiated it will be multiplied by dy/dx.17) Then you solve for dy/dx as if its a variable.18) Here lets review product rule:Take derivative of each termSolve for dy/dx using factoring:...

Solve the equation 36x^2 25=0 a. 6/5i b. 5/6i c. - id3622506556252152306, greyxxamber

Ответ:

gdhshwjfs

19.12.2021

Mathematics

For implicit differentiation, you are using the chain rule
$f'(x) = g'(u(x))* \frac{du}{dx}$
Except u(x) = y, So after every "y" term is differentiated it will be multiplied by dy/dx.

17) $y^3 +4 = 3x \\ 3y^2 \frac{dy}{dx} +0 = 3$
Then you solve for dy/dx as if its a variable.
$\frac{dy}{dx} = \frac{3}{3y^2} = \frac{1}{y^2}$

18) Here lets review product rule:
(fg)' = f'g + fg'

Take derivative of each term
$2x^2 = -3y^3 +3x^2y^3 \\ 4x = -9y^2 \frac{dy}{dx} + (6x)(y^3) + (3x^2)(3y^2 \frac{dy}{dx}) \\ 4x = -9y^2 \frac{dy}{dx} +6xy^3 +9x^2y^2 \frac{dy}{dx}$
Solve for dy/dx using factoring:
$4x - 6xy^3 = -9y^2 \frac{dy}{dx}+9x^2 y^2 \frac{dy}{dx} \\ 4x - 6xy^3 = \frac{dy}{dx}(-9y^2 +9x^2 y^2) \\ \frac{dy}{dx} = \frac{4x - 6xy^3}{-9y^2 +9x^2 y^2}$

0,0(0 оценок)

Solve the equation 36x^2 25=0 a. 6/5i b. 5/6i c. 25/36i d. 36/25i

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question