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kevonmajor
21.06.2019 •
Mathematics
Solve the problem. a student earned grades of c, a, b, and a in four different courses. those courses had these corresponding numbers of credit hours: 4, 5, 1, and 5. the grading system assigns quality points to letter grades as follows: a = 4, b = 3, c = 2, d = 1, and f = 0. compute the grade point average (gpa) and round the result to two decimal places. 3.40 3.50 8.75 2.18
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Ответ:
3.40
Step-by-step explanation:
Given :
A student earned grades of C, A, B, and A in four different courses.
Those courses had these corresponding numbers of credit hours: 4, 5, 1, and 5.
The grading system assigns quality points to letter grades as follows: A = 4, B = 3, C = 2, D = 1, and F = 0.
To Find: Compute the grade point average (GPA) and round the result to two decimal places.
Solution :
The grades earned are C, A, B, and A
Since . The grading system assigns quality points to letter grades as follows: A = 4, B = 3, C = 2, D = 1, and F = 0.
So the earned grades C=2 , A=4 , B=3 , A =4
Their corresponding numbers of credit hours are 4,5,1,5
Formula of GPA =![\frac{Grades*credits}{\text{sum of credits}}](/tpl/images/0001/2642/7f747.png)
=![\frac{4*2+4*5+3*1+4*5}{4+5+1+5}](/tpl/images/0001/2642/ac571.png)
=![\frac{8+20+3+20}{15}](/tpl/images/0001/2642/0128f.png)
=![\frac{51}{15}](/tpl/images/0001/2642/9b591.png)
= 3.40
Hence the grade point average (GPA) is 3.40
Ответ:
-3.6
Step-by-step explanation:
z/(-2) + -5 = -3.2 → times -2
z + 10 = 6.4
z = 6.4 - 10
z = -3.6