Solve the system by the addition 4x-5y=27 3x+3y=0

The original system of equations:
4x-5y=27
3x+3y=0

Step 1: Find a 'common ground' between either both x's or both y's using multiplication of the entirety of each equation. (I will do x).
(-3)4x-5y=27
(4)3x+3y=0
You need to make one of the factors negative so that the x's are opposites. Let's do the calculations now.
-12x+15y=-81
12x+12y=0
See how one is negative 12x and one is positive 12x?

Step 2: Now we cancel out the x's to find out what y equals. This leaves us with...
15y=-81
12y=0

Step 3: Now add your like terms.
27y=-81

Step 4: Divide each side by the coefficient.
27y÷27=-81÷27

y=-3

Step 5: Now we need to find x. Take any one equation from the original. I will be using 3x+3y=0 but you can use either one. Anywhere that you see a y in the equation, substitute it for -3.

3x+3(-3)=0

Now calculate.

3x-9=0

Then you want to move the -9 to the right side of the equation by doing inverse operations.

3x-9=0
+9 +9

3x=9

Finally, subtract both sides by the coefficient.

3x÷3=9÷3

x=3

You're solution is (3,-3)

Hope this helped!

0 | 3 8

1  | 2 2 4

2 | 0 1 3 6

3 | 4

Step-by-step explanation:

The first row is for numbers 0-9, the second row is for numbers 10-19, the third row is for numbers 20-29, and the fourth row is for numbers 30-39. The first column indicates the tens and the second column indicates the ones. Notice that 12 appears twice in the list and in the stem and leaf diagram. This diagram allows us to easily see the distribution of the data.