Mathematics: Solve the system using either gaussian elimination with back-substitution or gauss-jordan elimination. (if there is no solution, enter no solution. if there are an infinite number of solutions, set x3 and solve for x1 and x2. x1-3x3 =-5 3x1 x2 2x34 2x1 + 2x2 + x3 = 7 need ? read it talk to a tutor submit answer save progress practice another version 1 points larlinalg8 1.2.033 solve the system using either gaussian elimination with back-substitution or gauss-jordan elimination. (if there is no solution,

Solve the system using either gaussian elimination

robert7248

02.01.2022

x1=-4/5, x2=18/5 and x3=7/5

Step-by-step explanation:

$\left[\begin{array}{ccc|c}1&0&-3&-5\\3&1&2&4\\2&2&1&7\end{array}\right]$

you can do linear combination between the rows:

2nd row=R2-3R1 and 3th row=R3-2R1

$\left[\begin{array}{ccc|c}1&0&-3&-5\\0&1&11&19\\0&2&7&17\end{array}\right]$

3th row=(3R2-R3)/15

$\left[\begin{array}{ccc|c}1&0&-3&-5\\0&1&11&19\\0&0&1&\frac{7}{5} \end{array}\right]$

1st row=R1+3R3 and R2-11R3

$\left[\begin{array}{ccc|c}1&0&0&-4/5 \\0&1&0&18/5 \\0&0&1&7/5\end{array}\right]$

x1=-4/5, x2=18/5 and x3=7/5

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