Mathematics: Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution. u = x 4(x +1) x +1 (x + 1)2 select the solution(s) of the original equation. x = 1 + sqrt 2 x = 2 + sqrt 2 x = 3 + sqrt 2 x = 1 - sqrt 2 x = 2 - sqrt 2 x = 3 - sqrt 2

She feed her cat 65g a day and 1oz -28.3g 65/38.3=2.12oz a day 7 days in a week 2.12 multiplied by 7 then multiply that answer by 5 weeks. 2.12(7)=14.84(5)=74.2oz....

Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution.

Ответ:

kawsu

09.03.2022

Mathematics

For this case we have to:

Let u = x + 1

So:

u ^ 2-4u + 2 = 0

We have the solution will be given by:

$u = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}$

Where:

$a = 1\\b = -4\\c = 2$

Substituting:

$u = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (2)}} {2 (1)}\\u = \frac {4 \pm \sqrt {16-8}} {2}\\u = \frac {4 \pm \sqrt {8}} {2}\\u = \frac {4 \pm \sqrt {2 ^ 2 * 2}} {2}\\u = \frac {4 \pm2 \sqrt {2}} {2}$

The solutions are:

$u_ {1} = \frac {4 + 2 \sqrt {2}} {2} = 2 + \sqrt {2}\\u_ {2} = \frac {4-2 \sqrt {2}} {2} = 2- \sqrt {2}$

Returning the change:

$2+ \sqrt {2} = x_ {1} +1\\x_ {1} = 1 + \sqrt {2}\\2- \sqrt {2} = x_ {2} +1\\x_ {2} = 1- \sqrt {2}$

$x_ {1} = 1 + \sqrt {2}\\x_ {2} = 1- \sqrt {2}$

0,0(0 оценок)

Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution. u = x 4(x +1) x +1 (x + 1)2 select the solution(s) of the original equation. x = 1 + sqrt 2 x = 2 + sqrt 2 x = 3 + sqrt 2 x = 1 - sqrt 2 x = 2 - sqrt 2 x = 3 - sqrt 2

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question