Someone help me with this

find points a b c

<a=32

<b=40

<c=40

Step-by-step explanation:

to find angle a you have to subtract the 50 minus 180 to find the angle close to the 50 because angles in a straight line add up to 180. the answer will be

180-50=130

after finding the angle in that triangle you must add it to the other angle present which is 18° then subtract by 180 because angles in a straight line add up to 180

130+18+a=180

a=180-148

a=32 and that's how you find a

to find b you must know that the angle at the center is twice the angle at the circumference meaning the large angle C is 90°,now if it's 90° inorder to find the big angle B you must add the 18+90 then subtract 180

18+90+B=180

B=180-108

=72

since the combination of angle a and b will give you 72 you can find angle c by subtracting a from 72

c=72-32

=40

then if you look at angle c and angle b you can tell that they are alternating meaning angle b is also 40

I hope this helps

a_0 = -27

a_n = a_(n-1) * (-1/3)

Step-by-step explanation:

First evaluate given formula at n=0 and specify that as starting value

Then find how to get from n-1 to n by comparing two values. In this case the next value is formed by multiplying by -1/3.