Someone me with cal

a car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 44 ft/s2. what is the distance covered before the car comes to a stop? (give your answers correct to one decimal place.)

Since we are given a deceleration with a unit of ft/s2, it is convenient to convert 50 mi/h to ft/s. Appropriate conversion factors can be seen in the internet or in books. 

50 mi/h = 73.33 ft/s

the equation for the distance travelled is

x = Vo*t - 0.5*a*t^2

where 

x = distance travelled
Vo = initial velocity
t = time of travel
a = deceleration

since the time of travel is not known, we can find this using the equation

V = Vo - at

where V is the final velocity equal to zero (comes to stop)
substiruting values we get t = 1.67 s

therefore 

x = 61.1 ft (0.01 mi)

this relation is not a function.

Step-by-step explanation:

Given relation is

(-1, 3)   (1,-1)   (2,2)  and (1,3)

Now plot all the ordered pairs on the graph

Then we draw vertical lines through these points

If any vertical line crosses two points then this relation is not a function

The graph is attached below

We can see that the red vertical line crosses both points (1,-1) and (1,3)

It does not passes vertical line test.So this relation is not a function.