tatim210
16.07.2020 •
Mathematics
The average body mass index of children 9 years old is 18.4 with a standard deviation of 4.5. If it is known that the distribution is approximately normal, what is the body mass index of a 9-year-old child at the 82nd percentile
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Ответ:
Mass index for a 9-year-old child (at 82nd percentile ) = 22.51
Step-by-step explanation:
Given:
Mass index for a 9-year-old child = 18.4
Standard deviation = 4.5
Find:
Mass index for a 9-year-old child (at 82nd percentile )
Computation:
At 82nd percentile,
p-value = 0.82
p-value from Z table score = 0.9153
Mass index for a 9-year-old child (at 82nd percentile ) = Mass index for a 9-year-old child + p-value from Z table score(Standard deviation)
Mass index for a 9-year-old child (at 82nd percentile ) = 18.4 + 0.9153(4.5)
Mass index for a 9-year-old child (at 82nd percentile ) = 18.4 + 4.11
Mass index for a 9-year-old child (at 82nd percentile ) = 22.51
Ответ:
0.305
Step-by-step explanation:
When we use the percentage (%) notation, to express for example the happening of a success is X%, we are expressing that the corresponding fact is happening X times every 100 times. Instead of X% we could use X/100.
In this example, every 100 units of his payment check, Landon takes 30,5 unites and puts them to his saving account. So, instead of 30.5% we could say 30.5/100. (30.5% = 30.5/100).
So, we have:
30.5% = 30.5/100 = 0.305
This way, 0.305 is the decimal equivalent to 30.5%.
Observation: For avoiding comas in the latter fraction we could also say: 305/1000.