briannarose2003
19.07.2019 •
Mathematics
The equation of a parabola is given. y=−112x2−2x−1 what are the coordinates of the focus of the parabol
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Ответ:
IF the equation is y=−1/12x^2−2x−1
then -12y=x^2+24x+12
-12y+132=x^2+24x+144
-12(y-11)=(x+12)^2
so the vertex of the parabola is at (-12, 11)
semi axis length=12/4=3
the focus is at (-12, 11-3) = (-12, 8)
Ответ:
it is a concave parabola with focus at approx. (-0.0089, -0.9933)
Ответ:
11/5
Step-by-step explanation:
The answer would be 1 1/5
48/40 = 1 8/40
1 8/40 Simplify to 1 1/5