The exterior angles of a quadrilateral have measures of $72\degree,\ 58\degree,\ 2x\degree,$ and $3x\degree$ . Find the value of $x$ .

46degrees

Step-by-step explanation:

The sum of angles of exterior angles of a quadrilateral is 360 degrees

Hence;

72 + 58+2x+3x  = 360

130 + 5x  = 360

5x = 360-130

5x = 230

x  =230/5

x = 46 degrees

Hence the vale of x is 46degrees

A = 4

B = 2

2* (6 * 4) = 48

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