The fence around a rectangular piece of property is 156 meters long. if the area of the property is 1485 square meters, what are the dimensions of the property? (hint: set up the equations and
solve for y to graph.)

  33 by 45 meters

Step-by-step explanation:

The perimeter is twice the sum of adjacent side lengths, so the sum of the dimensions is 78 meters. If x is one of the dimensions, then 78-x is the other, and the area is their product:

  x(78 -x) = 1485

Subtracting the left side, we get ...

  x^2 -78x +1485 = 0

This can be graphed as ...

  y = x^2 -78x +1485

and the zeros will reveal the dimensions.

The attached graph shows them to be ...

  33 by 45 meters

1. Use a straightedge to draw line a and label a point on the line as point P. 2. Construct a line perpendicular to line a through point P. 3. Label a point on this line as point R. 4. With the compass open to the desired side length of the square, place the compass point on point P and draw an arc on line a and an arc on PRâ†â†’ . 5. Label the points of intersection as points S and T. 6. Keeping the same compass width, place the compass on point T and draw an arc in the interior of â SPT to intersect the previously drawn arc. 7. Label the point of intersection as point Q. 8. Without changing the compass width, place the compass point on point S and draw an arc in the interior of â SPT . 9. Use the straightedge to draw QSÂŻÂŻÂŻÂŻÂŻ and QTÂŻÂŻÂŻÂŻÂŻ.