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praveen35301
02.07.2019 •
Mathematics
The floor of a rectangular deck has a length that is 6 feet more than it’s width, x. hakeem is building the deck and decided to increase both dimensions by 3 feet. what is the new area, d, of the floor of the deck? a. x^2 + 12x + 27 b. x^2 + 9x + 18 c. x^2 + 9x d. x^2 +6x
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Ответ:
Let the width of the rectangular deck be = x feet
The length is 6 feet more than the width so length is = x+6 feet
Let us assume that a total 3 feet is increased (1.5 feet on both ends)
As Hakeem decided to increase both dimensions by 3 feet, this means 1.5 feet is increased on both sides of the deck. So, length and width increases by 3 feet each.
Hence, new length is = x+6+3 = x+9 feet
New width is = x+3 feet
So new area = length*width
D =![(x+9)(x+3)](/tpl/images/0041/9428/07f28.png)
=![x^{2}+3x+9x+27](/tpl/images/0041/9428/a4f20.png)
=
square feet
Hence, option A is correct.
Ответ:
1920
Step-by-step explanation:
20*8*12=1920