ambercombs
18.08.2019 •
Mathematics
The length of a rectangle is 2 cm less than 7 times the width. the perimeter is 60 cm. find the width and length.
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Ответ:
We know that perimeter its 2*length+2*width=60
Now we substitute our x and 7x-2
2*(7x-2)+2x=60
14x-4+2x=60 /+4
16x=64 /:16
x=4 - its the width
7*x-2, where x=4
28-2=26 - length
Ответ:
step 1: subtract 2x on both sides
2y + 2x ≥ 10
- 2x - 2x
2y ≥ -2x + 10
step 2: divide each number by 2
2y/2 ≥ -2x/2 + 10/2 = y ≥ -x + 5
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