Mathematics: The length of a rectangle is 55 times the width. the area is 845845 square yards. find the length and width of the rectangle.

The length of a rectangle is 55 times the width.

Ответ:

darwin59651

11.03.2022

Width = w

Length = 55 times w. Therefore, length = 55w

Area = width ⋅ length

Area = w ⋅ 55w

845,845 $yards^{2}$ = 55w ⋅ w

845,845 $yards^{2}$ = 55 $w^{2}$

Divide both sides by 55 to get "w" by itself.

$\frac{845,845 yards^{2} }{55}$ = $\frac{ 55w^{2} }{55}$

15,379 $yards^{2}$ = $w^{2}$

Now, take the square root of *both* sides in order to solve for "w."

$\sqrt{15,379 yards ^{2} } = \sqrt{ w^{2} }$

The square root of 15,379 simplifies to 13 $\sqrt{91}$ .

Therefore, width equals 13 $\sqrt{91}$ and length equals 55 times that.

Length equals 715 $\sqrt{91}$ .

Practically, you'll want to round those values (to the nearest hundredth is sufficient).

For a rectangle that is 845,845 $yards^{2}$ , the width is roughly 124.01 yards and the length is 6820.67 yards.

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The length of a rectangle is 55 times the width. the area is 845845 square yards. find the length and width of the rectangle.

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