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obedomari
19.06.2020 •
Mathematics
The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial population P0 has doubled in 5 years. Suppose it is known that the population is 9,000 after 3 years. What was the initial population P0? (Round your answer to one decimal place.)
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Ответ:
Step-by-step explanation:
Let P be the population of the community
So the population of a community increase at a rate proportional to the number of people present at a time
That is
Solve this equation we get
where p is the present population
p₀ is the initial population
If the initial population as doubled in 5 years
that is time t = 5 years
We get
Apply In on both side to get
Substitute
in
to get
Given that population of a community is 9000 at 3 years
substitute t = 3 in![{p(t)=p_oe^{\frac{In2}{5}t }}](/tpl/images/0690/3332/d438a.png)
![p(3)=p_oe^{3 (\frac{In2}{5}) }\\\\9000=p_oe^{3 (\frac{In2}{5}) }\\\\p_o=\frac{9000}{e^{3(\frac{In2}{5} )}} \\\\=5937.8](/tpl/images/0690/3332/02615.png)
Therefore, the initial population is 5937.8Ответ:
81
Step-by-step explanation:
9 + 9 + (21 x 3) = 18 + 63 = 81
NOTE : ALL VALUES ABOVE ARE CM²
i just didnt want to write it over and over again