The question is in the picture. and can you also find the perimeter?   i'm lost

For corresponding sides we can write

1) BN/PQ=AI/WE

10/4 = 12.5/(2x+1)

2x+1 = 12.5*4/10

2x+1 =5

2x=4

x=2

2) BN/PQ=IN/EQ

10/4 = 17.5/14z

14z = 17.5*4/10

14z = 7

z= 1/2 =0.5

3) BN/PQ=RB/OP

10/4=(y+5)/4.5

y+5 = 10*4.5/4=11.25

y=6.25

4) P(AINBR)=12.5+17.5+10+11.25+7.5 = 58.75

P(WEQPO)=5+7+4+4.5+3=23.5

Check: Ratio of the sides=ratio of the perimeters =2.5

BN/PQ=10/4=2.5

P(AINBR)/P(WEQPO)=58.75/23.5 =2.5.

-8

Step-by-step explanation:

X÷4 = 5-7

X÷4 = -2

X = -2 × 4

X = -8