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sammiehammer
30.03.2020 •
Mathematics
The radius of a spherical ball is measured at r = 25 cm. Estimate the maximum error in the volume and surface area if r is accurate to within 0.6 cm. (Round your answers to three decimal places.)
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Ответ:
Volume = 2384.582 cm^3
Surface Area = 189.626 cm^2
Step-by-step explanation:
With the accuracy of r within 0.6 cm minimum & maximum values are 25-0.3 and 25+0.3 respectively.
Taking r = 25 cm
Volume = (4/3)*Pi*R3 = 65449.847
Surface Area = 4*Pi*R2 = 7853.982
The minimum possible values for Volume and surface area would be:
if r = 24.7 cm
Volume = (4/3)*Pi*R3 = 63121.814 cm^3
Surface Area = 4*Pi*R2 = 7666.617 cm^2
The maximum possible values for Volume and surface area would be:
if r = 25.3 cm
Volume = (4/3)*Pi*R3 = 67834.429 cm^3
Surface Area = 4*Pi*R2 = 8043.608 cm^2
Error from Minimum values:
Volume = 2328.033 cm^3
Surface Area = 187.365 cm^2
Error from Maximum values:
Volume = 2384.582 cm^3
Surface Area = 189.626 cm^2
Ответ:
3/2 is the correct answer