The sim of three consecutive integers is -204. what is the largest integer?

To find the largest integer, we must know what the smallest is first. Let the smallest be x. Note that it is consecutive, and so the other numbers are 1 greater and 2 greater than x.

Set the equation:

(x) + (x + 1) + (x + 2) = -204

Simplify. Combine like terms

(x + x + x) + (1 + 2) = -204

3x + 3 = -204

Isolate the x. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 3 from both sides

3x + 3 (-3) = -204 (-3)

3x = -207

Next, divide 3 from both sides

3x/3 = -207/3

x = -207/3

x = -69

-69 is the smallest number. To find the largest integer, plug it back in to (x + 2)

x = -69

-69 + 2= -67

-67 is your largest integer.

hope this helps

Let the largest of the three integers be x. The next smaller one is x - 1, and the smallest is x - 2.

Now we add them and set the sum equal to -204.

x + x - 1 + x - 2 = -204

3x - 3 = -204

3x = -201

x = -67

The largest integer is -67.

The value of y would be 12

Step-by-step explanation:

To find this, follow the steps for solving single variable equations.

-3y - 12 = -4y > Add 3y to both sides

-12 = -y > Divide both sides by -1

12 = y