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aron7596
29.09.2019 •
Mathematics
The standard for of the equation of a parabola is y=x^2+4x+11. what is the vertex for of the equation?
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Ответ:
or easier
for y=ax²+bx+c
the x value of the vertex is
and the y value is found by subsituting the x value in for x
so
y=1x²+4x+11
a=1
b=4
the x value of the vertex is
the y value is found by subsituting -2 for x
y=(-2)²+4(-2)+11
y=4-8+11
y=7
the vertex is (-2,7)
Ответ: