hdjehd
18.10.2019 •
Mathematics
The value of y varies directly with x^2, and y = 64 when x = 4. what is the value of y when x = 6?
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Ответ:
y = kx²
64 = k*4²
64 = k*4*4
64 = 16k
64/16 = k
4 = k
k = 4
y = kx²
y = 4*6²
y = 4*6*6
y = 144
Ответ:
e
Step-by-step explanation: