The width of a rectangle is 2 cm less than its length. the perimeter is 52 cm. the length is:

If the width is 2 cm less than its length, the expression is this: w = L - 2.  The length then is just L.  The perimeter formula is 2L + 2w = P.  Filling in accordingly, we have 2L + 2(L-2)=52 and 2L + 2L - 4 = 52.  4L = 56 and L=14.  The width then is 12.  There you go!

4:18 pm

Step-by-step explanation:

An airport offers 2 shuttles that run on different schedules.If both shuttles leave the airport at 4:00 p.m.,at what time will they next leave theairport together.

Shuttle A leaves every 6 minutes

Shuttle B leaves every 9 minutes

Solution

To solve for when next both shuttles will leave the airport together, find the least common multiples of 6 minutes and 9 minutes

Shuttle A (every 6 minutes) = 6, 12, 18, 24

Shuttle B (every 9 minutes) = 9, 18, 27, 36

The least common multiples of 6 minutes and 9 minutes is 18 minutes

4:00 pm + 18 minutes

= 4:18 pm

The next time both shuttles will leave theairport together is 4:18 pm of the same day