The x-axis contains the base of an equilateral triangle rst. the origin is at s. vertex t has coordinates (2h, 0) and the y-coordinate of r is g, with g > 0.

enter the coordinates for the midpoint of st:

enter the x- coordinate of r:

Coordinates of Mid Point of ST is ( h , 0 ) and x-coordinate of R is   .

Step-by-step explanation:

Given: Coordinate of S ( 0 , 0 )  ,  Coordinate of T ( 2h , 0 )

           y-coordinate of R = g

Coordinates of Mid point of ST =

                                                    = ( h , 0 )

let x-coordinate of point R be x

Distance of RS = Distance of ST

Squaring both sides, we get

So, x-coordinate of R is

Therefore, Coordinates of Mid Point of ST is ( h , 0 ) and x-coordinate of R is   .

Step-by-step explanation:

Given precision is a standard deviation of s=1.8, n=12,  target precision is a standard deviation of σ=1.2

The test hypothesis is

H_o:σ <=1.2

Ha:σ > 1.2

The test statistic is

chi square =

=

=24.75

Given a=0.01, the critical value is chi square(with a=0.01, d_f=n-1=11)= 3.05 (check chi square table)

Since 24.75 > 3.05, we reject H_o.

So, we can conclude that her standard deviation is greater than the target.