Then th term of sequence X is an + b Thenth term of sequence Yis bn + a
The 2nd term of sequence X is equal to the 3rd term of sequence Y.
It can be shown that a = 2b
Write
nth term of sequence X
rth term of sequence Y
in terms of n only.

B(-6, 0)

Step-by-step explanation:

You want to find B such that ...

(B -A) = (3/4)(C -A) . . . . the required distance relation

4(B -A) = 3(C -A) . . . . . . multiply by 4

4B = 3C +A . . . . . . . . . . add 4A, simplify

Now, we can solve for B and substitute the given coordinates:

B = (3C +A)/4 = (3(-6, -2) +(-6, 6))/4 = (-24, 0)/4 = (-6, 0)

The coordinates of point B are (-6, 0).

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Tysm!

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