Mathematics: There are 6 people in a raffle drawing, two raffle winners each win gift cards, each gift card is the same. how many ways are there to choose the winners? decide if the situation involves a permutation or a combination, and then find the number of ways to choose the winners.

There are 6 people in a raffle drawing, two raffle

Ответ:

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14.03.2022

B. Combination: Number of ways = 15

Step-by-step explanation:

2 winners are to be chosen out of 6 people participating in the raffle drawing. In this case the order of selection does not matter, therefore, this situation involves combinations

So, we have to find combinations of 6 people taken 2 at a time. This can be represented by 6C2. The general formula for combinations is:

$^{n}C_{r}=\frac{n!}{r!(n-r)!}$

In this case n = 6 and r = 2. Using these values, we get:

$^{6}C_{2}=\frac{6!}{2! \times (6-2)!} \\\\ ^{6}C_{2}= \frac{6!}{2! \times 4!}\\\\ ^{6}C_{2}=\frac{6 \times 5 \times 4!}{2 \times 4!}\\\\ ^{6}C_{2}= \frac{30}{2}\\\\ ^{6}C_{2}= 15$

Thus, there are 15 ways to chose the winners. So, option B gives the correct answer.

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There are 6 people in a raffle drawing, two raffle winners each win gift cards,
each gift card is the same. how many ways are there to choose the winners?
decide if the situation involves a permutation or a combination, and then find
the number of ways to choose the winners.

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