This robotic arm is made up of two cylinders with equal volume and two triangular prism hands. The volume of each hand is

1

2 r ×
1

3

r ×

2r, where r is the radius of the cylinder's base. What fraction of the total volume do the robotic hands take up?

Step-by-step explanation:

Since the height isn't given, we assume it to be "h" (of cylinders). And the answer will be in terms of "r" and "h".

The area of 1 arm is given, so the area of 2 arms would be:

Now, area of 2 cylinders would be the formula:

So, total area is A_arm PLUS A_cyl. The fractional area the arms are would be gotten by taking expression A_arm  divided  by A_total.

Shown below:

We simplify further:

THis is the answer.

r/(9.42H + r),

where H is each cylinder's height

Step-by-step explanation:

Volume of hands:

2 × ½t × ⅓r × 2r = ⅔r³

Let H be the height of each cylinder

Total volume:

2(3.14×r²×H) + ⅔r³

(6.28H + ⅔r)r²

Ratio:

[⅔r³] ÷ (6.28H + ⅔r)r²

r ÷ (9.42H + r)

r/(9.42H + r)

It is the tenths place. 109.7 is greater than 109.6