Three joggers are running around a circular track. one of them completes one lap in 6 minutes, the second one in 9 minutes, and the third one in 15 minutes. what time will they arrive at their starting point together if they start at the same time from the same point at 10: 00 am and maintain their jogging pace

At 11:30 am they will arrive at their starting point together

Step-by-step explanation:

we know that

One of them completes one lap in 6 minutes

The second one in 9 minutes

The third one in 15 minutes

step 1

Find the least common multiple (LCM)

6=2*3

9=3²

15=3*5

so

LCM=(3²)*(2)*(5)=90 minutes

step 2

Find the number of laps of each jogger for the LCM

jogger 1

90/6=15 laps

jogger 2

90/9=10 laps

jogger 3

90/15=6 laps

If they start at 10:00 am

then

10:00 am + 90 minutes=11:30 am

This is pythagorus theorem which is c squared equals a squared plus b squared,

12 squared minus 6 squared equals 108, square root of 108 is 10.39, i don’t know if u have to round it to a decimal place but if u do, tell me