Mathematics: Three numbers are chosen at random. the middle number is 5 more than the smallest number. the largest number is two times the smallest number. the sum of the 3 numbers is 53. what is the smallest number?

Three numbers are chosen at random. the middle - id2348157, ineedtopeebeforethec

Ответ:

kaylarenee05080

02.01.2022

Smallest + Middle + Largest = 53
M= S + 2
L = 2S

Substitute M= S +2 and L = 2S into S + M + L =53

S + S + 2 + 2S = 53
4S + 2 = 53
- 2 -2

4S = 51
4S/4 = 51/4
S = 12.75

M = S + 2
M = 12.75 + 2
M = 14.75

L= 2S
L = 2 (12.75)
L = 25.5

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Ответ:

anthonyhaywood

17.10.2021

Mathematics

Slope=3/4

Step-by-step explanation:

1) Label all values with x1 y1, x2 y2

Then, plug jn each value into this equation:y2-y1/x2-x1

Remember that negative values will become positive when dealjng with a subtraction sign.

5-(-1)=5+1.

= 6/8

6-(-2)=6+2

After getting 6/8, simplify by the gcf (2) to get 3/4

3/4

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Three numbers are chosen at random. the middle number is 5 more than the smallest number. the largest number is two times the smallest number. the sum of the 3 numbers is 53. what is the smallest number?

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