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yoyo4396
16.12.2021 •
Mathematics
Two hot air balloons are traveling along the same path away from a town,
beginning from different locations at the same time. Henry's balloon begins
25 miles from the town and is 37 miles from the town after 2 hours. The
distance of Tasha's balloon from the town is represented by the function y =
7x+15.
Which balloon was farther from the town at the beginning, and which traveled
more quickly?
A. Henry's balloon was farther from the town at the beginning, but
Tasha's balloon traveled more quickly.
B. Tasha's balloon was farther from the town at the beginning, but
Henry's balloon traveled more quickly
C. Tasha's balloon was farther from the town at the beginning, and it
traveled more quickly.
D. Henry's balloon was farther from the town at the beginning, and it
traveled more quickly.
Solved
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Ответ:
Explanation:
if ramin's house number = 3 yuza's
then choices are: n×3
1 , 3 | 2 , 6 | 3 , 9 | 4 , 12 | 5 , 13 | 6 , 18 | 7 , 21
since there are 13 house between yuza and ramin
thus it's 7 , 21 (because there's 13 numbers between 7 and 21)
yuza lives in house 7
ramin live in house 21
and since houses between yuza and glonti = 3 times houses between glonti and ramin, with a ratio of 3:1
13 - 1 = 12 (we subtracted 1 for glonti's house)
3:1 , 3+1=4
12/4=3
3×3=9
hence
9 and 3 are the numbers of houses in each side with glonti in the middle
9 houses - glonti's house - 3 houses
7 + 9 = 16 (yuza's house number 7 plus 9 houses ahead)
glonti lives in the house: 16 + 1 = 17