Two sides of a parallelogram are 49 feet and - id497812520477, ramberson101

Ответ:

emilylittle2442

12.05.2021

$A=3276\ ft^2$

Step-by-step explanation:

Given that,

The sides of a parallelogram are 49 feet and 78 feet. The measure of the angle between these sides is 59º.

We need to find the area of the parallelogram.

Using trigonometry,

$\sin(59)=\dfrac{h}{49}\\\\h=\sin(59)\times 49\\\\h=42.00\ ft$

We know that,

Area = base (b) × height (h)

So,

$A=78\times 42.00\\\\A=3276\ ft^2$

So, the area of the parallelogram is equal to $3276\ ft^2$ .

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rosarioemily580

12.07.2022

They will have the same amount on week 20

Step-by-step explanation:

I posted a picture on how I got my answer

Hope this Helped

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