niquermonroeee
25.05.2021 •
Mathematics
Uhh I’m doing math work and I need help! I’m doing Solve the system of linear equations using substitution. And I have this problem and I keep getting -6 for y but the right answer for y is positive 6; can someone tell me what I’m doing wrong?!?
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Ответ:
x=0 and y=6
Step-by-step explanation:
First, you would solve x=y-6 for x.
x=y-6 so you substitute the x in -6x-2y=-12 with (y-6)
-6x-2y=-12 → -6(y-6)-2y=-12
Simplify both sides of the equation = -8y+36=-12
Add -36 to both sides to remove it = -8y+36+-36=-12+-36
-8y+36+-36=-12+-36 → -8y=-48
Divide both sides by -8 to remove it. → y=6
I believe where you went wrong was with where you substituted y-6.
y-6 is the substitute for x so in parenthesis you would put (y-6) where x is in -6x-2y=-12 making the new equation -6(y-6)-2y=-12.
Ответ: