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mlandon922
12.10.2019 •
Mathematics
Urgent
fluorine-20 has a half-life of 11 seconds. identify the amount of fluorine-20 left from a 25 gram sample after 55 seconds.
a 0.78125 g
b 78125 mg
c 0.6352 g
d 7.8124 g
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Ответ:
A. 0.78 g
Step-by-step explanation:
The half-life of F-20 (11 s) is the time it takes for half of it to decay.
After one half-life, half (50 %) of the original amount will remain.
After a second half-life, half of that amount (25 %) will remain, and so on.
We can construct a table as follows:
No. of Fraction Mass
half-lives t/s Remaining Remaining/g
0 0 1 25
1 11 ½ 12.5
2 22 ¼ 6.2
3 33 ⅛ 3.1
4 44 ¹/₁₆ 1.6
5 55 ¹/₃₂ 0.78
6 66 ¹/₆₄ 0.39
We see that 0.78 g of F-20 remain after five half-lives (55 s).
Ответ:
For Plato users, the answer is 1,939,372.1
Step-by-step explanation:
You use the equasion: Population=(initial population)(e)^(growth×time)
So P=(1,300,000)(e)^(0.04×10)
**NOTE: e is not a variable, e is a number!!! just like how pi equlas 3.14... e equals 2.7...**
So plug the letter e (which is 2.71828...) into the calculator when doing equasion and do not solve for e