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Alex9089435028
31.10.2021 •
Mathematics
us The quadratic functions f and g are defined by f(x) = 4x² +p, XER - = g(x) = x² +qx + p, x-ER where p, q and r are non-zero constants such that p =-2r and q=-3r. Given that (x +r) is a factor of f and g. Determine the value of p, q and r. Hence, factorise f and g completely.
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Ответ:
9514 1404 393
(p, q, r) = (-1, -3/2, 1/2)f(x) = (2x -1)(2x +1)g(x) = (x -2)(x +1/2)Step-by-step explanation:
Substituting for p in the equation for f(x), we can use synthetic division to find the value of r that makes the remainder zero from division by (x +r).
To make (x+r) be a factor, the remainder (4r² -2r) must be zero. That factors as ...
2r(2r -1) = 0 ⇒ r = 1/2; r = 0 is disallowed by the problem statement
Then p = -2r = -1, and q = -3r = -3/2.
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The functions with the values filled in are ...
f(x) = 4x² -1 = (2x -1)(2x +1)
g(x) = x² -3/2x -1 = (x -2)(x +1/2)
Ответ:
For this case we have the following quadratic equation:
Applying the quadratic formula we have:
Where:
Substituting we have:
We have two roots:![x_ {1} = \frac {-71.55} {32} = - 2.24\\x_ {2} = \frac {71.55} {32} = 2.24](/tpl/images/0158/3523/367c5.png)
Option B