Use the piecewise function to evaluate points f(–5), f(0), and f(2). Question 9 options:

A)

f(–5) = –11, f(0) = 0, and f(2) = 3

B)

f(–5) = –15, f(0) = 0, and f(2) = 6

C)

f(–5) = –11, f(0) = –1, and f(2) = 6

D)

f(–5) = –11, f(0) = 0, and f(2) = –1

Use the piecewise function to evaluate points f(–5), f(0), and f(2).

Question 9 options:
A)
f(–5

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Ответ:

hargunk329

11.10.2020

Mathematics

The value of x, the larger number, is equal to 25.The value of y, the smaller number, is equal to 20.

x = 5 + y

4x = 5y

Because we already have a value for x, we can solve for the exact value of y.

4(5 + y) = 5y

Distributive property.

20 + 4y = 5y

Subtract 4y from both sides.

y = 20

Now that we have the exact value of y, we can solve for x.

x = 5 + 20

x = 25

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Use the piecewise function to evaluate points f(–5), f(0), and f(2). Question 9 options: A) f(–5) = –11, f(0) = 0, and f(2) = 3 B) f(–5) = –15, f(0) = 0, and f(2) = 6 C) f(–5) = –11, f(0) = –1, and f(2) = 6 D) f(–5) = –11, f(0) = 0, and f(2) = –1