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19deleonl

19deleonl

24.06.2019 •

Mathematics

Use the unit circle to find the six trigonometric ratios(sine,cosine,tangent,cosecant,secant, and cotangent) for the angles listed below. , and show work i will say and mark the !

Use the unit circle to find the six trigonometric ratios(sine,cosine,tangent,cosecant,secant, and co

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Ответ:

aronandalp3yep6

09.03.2022

$\theta=\dfrac{11\pi}6$ behaves the same as $\theta=-\dfrac\pi6$ , since $-\dfrac\pi6+2\pi=\dfrac{11\pi}6$ . Recall that $\cos(-x)=\cos x$ and $\sin(-x)=-\sin x$ . Then

$\sin\dfrac{11\pi}6=-\sin\dfrac\pi6=-\dfrac12$

$\cos\dfrac{11\pi}6=\cos\dfrac\pi6=\dfrac{\sqrt3}2$

$\tan\dfrac{11\pi}6=\dfrac{\sin\frac{11\pi}6}{\cos\frac{11\pi}6}=-\dfrac1{\sqrt3}$

$\csc\dfrac{11\pi}6=\dfrac1{\sin\frac{11\pi}6}=-2$

$\sec\dfrac{11\pi}6=\dfrac1{\cos\frac{11\pi}6}=\dfrac2{\sqrt3}$

$\cot\dfrac{11\pi}6=\dfrac1{\tan\frac{11\pi}6}=-\sqrt3$

- - -

$\theta=-\dfrac{7\pi}4$ behaves the sames as $\theta=\dfrac\pi4$ , since $\dfrac\pi4-2\pi=-\dfrac{7\pi}4$ . Then

$\sin\left(-\dfrac{7\pi}4}\right)=\sin\dfrac\pi4=\dfrac1{\sqrt2}$

$\cos\left(-\dfrac{7\pi}4\right)=\cos\dfrac\pi4=\dfrac1{\sqrt2}$

$\tan\left(-\dfrac{7\pi}4\right)=1$

$\csc\left(-\dfrac{7\pi}4\right)=\sqrt2$

$\sec\left(-\dfrac{7\pi}4\right)=\sqrt2$

$\cot\left(-\dfrac{7\pi}4\right)=1$

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Ответ:

RanaA5515

17.11.2022

If you are asking for an answer in ratio form, here!
66:89.1

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