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cathydaves
15.05.2021 •
Mathematics
Wavelength and Frequency
Determine the ratio of the notes to middle C.
Express the answers as a simple integer ratio. (Ratios will be approximate due to rounding.)
The smaller the numbers in the ratio, the greater the consonance. Decide which of the notes when played with middle C would have the greatest dissonance.
a. G and C
b. B and C
c. D and C
d. E and C
Please select the best answer from the choices provided
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Ответ:
B. B and C
Step-by-step explanation:
I calculated it logically
Ответ:
Complete Question
One consequence of the popularity of the internet is that it is throughout to reduce television watching. Suppose that a random sample of 55 individuals who consider themselves to be avid Internet users results in a mean time of 2.10 hours watching television on a weekday. The standard deviation is![\sigma = 1.93](/tpl/images/0724/0003/76a62.png)
Required:
Determine the likelihood of obtaining a sample mean of 2.10 hours or less from a population whose mean is presumed to be 2.45 hours.
The likelihood is![P(X \le 2.10 ) = 0.08931](/tpl/images/0724/0003/ac1f7.png)
Step-by-step explanation:
From the question we are told that
The sample size is![n = 55](/tpl/images/0724/0003/6cd86.png)
The population mean is![\mu = 2.45 \ hours](/tpl/images/0724/0003/9692d.png)
The random mean considered![\= x = 2.10 \ hours](/tpl/images/0724/0003/ad14e.png)
Generally the standard error of mean is mathematically represented as
=>![\sigma _{\= x } = \frac{1.93 }{ \sqrt{55} }](/tpl/images/0724/0003/1c413.png)
=>![\sigma _{\= x } = 0.2602](/tpl/images/0724/0003/e4593.png)
The likelihood of obtaining a sample mean of 2.10 hours or less from a population whose mean is presumed to be 2.45 hours is mathematically represented as
Generally![\frac{X - \mu }{\sigma_{\= x }} = Z(The \ standardized \ value \ of \ X )](/tpl/images/0724/0003/48944.png)
From the z-table the value of
So