What are the vertex and x-intercepts of the graph of the function below? y =(x + 4)(x + 2)

In the form y=ax^2+bx+c
the x value of the vertex is -b/2a

the x intercept is where th e linecrosses the x axis or where y=0

expand
(x+4)(x+2)=x^2+6x+8
a=1
b=6
x value of vertex=-6/2(1)=-6/2=-3
sub back to find y value
(-3)^2+6(-3)+8
9-18+8
-1
y value is -1
vertex is (-3,-1)

x intercept
set to zero
0=(x+4)(x+2)
set each to zero
0=x+4
-4=x
x+2=0
x=-2
x intercept are at (-4,0) and (-2,0)

vertex is (-3,-1)
x ints are at (-4,0) and (-2,0)

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