What are the vertical and horizontal asymptotes for the function 3x^2/x^2-4

vertical asymptotes: x = 2, x = -2

              horizontal asyptote: y = 3

Step-by-step explanation:

Vertical Asymptotes are the restrictions on "x", which is denoted by the denominator being unequal to zero.

x² - 4 = 0

(x + 2)(x - 2) = 0

x + 2 = 0      and       x - 2 = 0

     x = -2     and             x = -2

Horizontal Asymptotes are determined by the degree of the numerator (n) compared to the degree of the denominator (m) as follows:

If n > m , then no horizontal asymptote (use long division to find slant asymptote)If n = m , then horizontal asymptote is coefficient of n divided by coefficient of mIf n < m , then horizontal asymptote is: y = 0

In the given problem, the degree of both the numerator and denominator is 2 so horizontal asymptote is:

The answer would be 12.99% and $187,000.

Solution:
(1.031^4(15) = ( 1+r)^15
60 log 1.031 = 15 log (1 + r)
4log (1.031) = log ( 1 + r)

10^[4log(1.031)] = r + 1

10^[4log (1.031) ] - 1 =
r = 0.1299
= about 12.99%