What is 7 4/5 as an improper fraction

The answer is 39/5. this is because you multiply the whole number by the denominator and add the result to your numerator. Your denominator stays the same.

The figure of this problem was not found, however, it can be solved and explained for didactic purposes.we know thatthe surface area of a cube=6*b²where b is the length side of a cubecase a) 1 in2sa=1 in²sa=6b²b=√(sa/> b=√(1/6) > b=√6/6 inif on the net the cube length is (√6/6) in, then the surface area will be 1 in²case  b) 6 in2sa=6 in²sa=6b²b=√(sa/> b=√(6/> 1 inif on the net the cube length is (1) in, then the surface area will be 6 in²case  c) 12 in2  sa=12 in²sa=6b²b=√(sa/> b=√(12/> √2  inif on the net the cube length is (√2) in, then the surface area will be 12 in²case  d) 14 in2  sa=14 in²sa=6b²b=√(sa/> b=√(14/> √(7/3)  inif on the net the cube length is (√(7/3) in, then the surface area will be 14 in²