What is the completely factored form of f(x)=x3−7x2+2x+4? f(x)=(x+1)(x−(3+52−−√))(x−(3−52−−√))

f(x)=(x−1)(x−(3+13−−√))(x−(3−13−−√))

f(x)=(x+1)(x−(3+13−−√))(x−(3−13−−√))

f(x)=(x−1)(x−(3+52−−√))(x−(3−52−−√))

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Ответ:

Mckenzie8062

22.03.2021

Mathematics

x ≈ −0.13 and x ≈ 1.53

Step-by-step explanation:

Here, the given equation is,

5x^2-7x=1

$\implies x^2 - \frac{7}{5}x=\frac{1}{5}$

$\implies x^2 - \frac{7}{5}x + \frac{49}{100} =\frac{1}{5}+\frac{49}{100}$

$\implies (x-\frac{7}{10})^2=\frac{20+49}{100}$

$\implies (x-\frac{7}{10})^2=\frac{69}{100}$

$\implies (x-\frac{7}{10}) = \pm\sqrt{\frac{69}{100}}$

$\implies x=\frac{7}{10} \pm\sqrt{\frac{69}{100}}$

Thus,

$x=\frac{7}{10}+\sqrt{\frac{69}{100}}=1.53066238629\approx 1.53$

$x=\frac{7}{10}-\sqrt{\frac{69}{100}}=-0.13066238629\approx -0.13$

Thus, the solution of the given equation are x ≈ 1.53 and x ≈ -0.13.

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What is the completely factored form of f(x)=x3−7x2+2x+4? f(x)=(x+1)(x−(3+52−−√))(x−(3−52−−√)) f(x)=(x−1)(x−(3+13−−√))(x−(3−13−−√)) f(x)=(x+1)(x−(3+13−−√))(x−(3−13−−√)) f(x)=(x−1)(x−(3+52−−√))(x−(3−52−−√))